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Give your students feedback,

meaningfully and efficiently.

## Students Show Step-by-Step Work

## Embrace Visual Learning

## Simultaneously Review All Assignments

## Analytics Show Where Students Struggled

## No Accounts Or Downloads Required

## Office Hours

## Great for Many Areas of Math

### Algebra

### Calculus

### Physics

meaningfully and efficiently.

Students can start with a blank Free Math document, copying down and working through problems just as they would in paper notebooks.

Students save their work as a file and submit it through an LMS in response to an assignment.

Students can include images in their solutions.

Including quickly snapping a picture of written work with their webcam.

Complete solutions are shown, grouped by similar final answer.

You can award partial credit and give feedback to students that need help.

You don't need to type in an answer key, Free Math just provides an organized view of all student work.

Give feedback on the most impactful problems first,

everything else gets completion points.

The entire experience runs right in your web browser.

Assignments and grading sessions save directly from the browser to files in your downloads folder. From there you can store the files in any cloud system like Google Drive, Dropbox, OneDrive, etc.

The files can easily be collected in any LMS, downloaded all together and loaded for grading. After grading, your LMS also easily provides an individual feedback file to each student.

Have questions about how to get started with Free Math?

Want to talk with the development team about a feature suggestion?

Interested in meeting other teachers improving their classrooms with Free Math?

Come to office hours on Google Meet, held Monday, Wednesday and Friday at 8:30-9:30am CST

$\frac{1}{x-4}+\frac{2}{x^2-16}=\frac{3}{x+4}$

$\frac{1}{x-4}+\frac{2}{\left(x-4\right)\left(x+4\right)}=\frac{3}{x+4}$

$\frac{1}{x-4}\cdot\left(\frac{x+4}{x+4}\right)+\frac{2}{\left(x-4\right)\left(x+4\right)}=\frac{3}{x+4}\cdot\left(\frac{x-4}{x-4}\right)$

$\frac{1\left(x+4\right)}{\left(x-4\right)\left(x+4\right)}+\frac{2}{\left(x-4\right)\left(x+4\right)}=\frac{3\left(x-4\right)}{\left(x+4\right)\left(x-4\right)}$

$1\left(x+4\right)+2=3\left(x-4\right)$

$x+6=3x-12$

$x+18=3x$

$18=2x$

$9=x$

$\int x\ln xdx$

$u=\ln x$

$dv=xdx$

$du=\frac{1}{x}dx$

$v=\frac{x^2}{2}$

$\int x\ln sdx=\frac{x^2}{2}\ln x-\int\frac{x^2}{2}\cdot\frac{1}{x}dx$

$\frac{x^2}{2}\ln x-\frac{1}{2}\int xdx$

$\frac{x^2}{2}\ln x-\frac{1}{2}\left(\frac{x^2}{2}\right)+c$

$\frac{x^2}{2}\ln x-\frac{1}{4}x^2+c$

$\text{A ball is thrown from 1 m above the ground.}$

$\text{It is given an initial velocity of 20 m/s}$

$\text{At an angle of 40 degrees above the horizontal}$

$\text{Find the maximum height reached}$

$\text{And velocity at that point}$

$x\left(t\right)=v\cos\left(\theta\right)t=20\cos\left(40\right)t=15.3t$

$y\left(t\right)=y_0+v\sin\left(\theta\right)t-\frac{9.8t^2}{2}$

$y\left(t\right)=1+20\sin\left(40\right)t-4.9t^2$

$y\left(t\right)=1+12.9t-4.9t^2$

$v_y\left(t\right)=v\sin\left(\theta\right)-9.8t$

$v_y\left(t\right)=12.9-9.8t$

$\max\ height\ at\ v_y\left(t\right)=0$

$12.9-9.8t=0$

$-9.8t=-12.9$

$t=\frac{-12.9}{-9.8}=1.3$

$y\left(1.3\right)=1+12.9\left(1.3\right)-4.9\left(1.3\right)^2$

$y\left(1.3\right)=9.5\ m$

$y\ component\ of\ velocity\ is\ 0\ at\ highest\ pt$

$total\ velocity\ =v_x=15.3\ \frac{m}{s}$

Free Math is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
Free Math is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with Free Math. If not, see <http://www.gnu.org/licenses/>.